F(p)=-80p^2+2560p-17,600

Solution for F(p)=-80p^2+2560p-17,600 equation:

(F)=-80F^2+2560F-17.600

We move all terms to the left:

(F)-(-80F^2+2560F-17.600)=0

We get rid of parentheses

80F^2-2560F+F+17.600=0

We add all the numbers together, and all the variables

80F^2-2559F+17.6=0

a = 80; b = -2559; c = +17.6;
Δ = b2-4ac
Δ = -25592-4·80·17.6
Δ = 6542849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2559)-\sqrt{6542849}}{2*80}=\frac{2559-\sqrt{6542849}}{160}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2559)+\sqrt{6542849}}{2*80}=\frac{2559+\sqrt{6542849}}{160}
$